Question

Sine and Cosine of Complementary Angles

Answer 1

First, do you know what Complementary Angles are?

Answer 2

yes

Answer 3

90 degrees right

Answer 4

OK, then what does the \(90^\circ - A\) do?

Answer 5

like a subtract what A is ?

Answer 6

i still dont get it

Answer 7

OK. Well, lets try the triangular version. This will use a right triagle because that makes the 90 part work.

Answer 8

sinA = a/h
cosB = a/h

Right?

There is a relationship.

In a right triangle:
\(\measuredangle \)A = \(90^\circ - \measuredangle \)B

Answer 9

Now look at the tangents of them both, since that is what the question asks about:

tanA=a/b
tanB=b/a

And because A = 90-B:

tan(90-B)=a/b

Answer 10

Are you seeing where I am going with this?

Answer 11

ohh yesss i am

Answer 12

thank you