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Mathematics 11 Online
OpenStudy (anonymous):

using set builder notation, what is the domain for the function f(x): (down below)

OpenStudy (anonymous):

\[f(x) = \frac{ 1 }{ \sqrt{3-x} }\]

OpenStudy (anonymous):

your job is to solve \[3-x>0\] which should only take one step

OpenStudy (anonymous):

let me know what you get, then we can put it in set builder notation

OpenStudy (anonymous):

3-2>0

OpenStudy (anonymous):

@satellite73

OpenStudy (anonymous):

you are trying to solve for \(x\) in \[3-x>0\] add \(x\) to both sides

OpenStudy (anonymous):

ohhh oops

OpenStudy (anonymous):

3>0x ?

OpenStudy (anonymous):

\[3>x\]

OpenStudy (anonymous):

no wait

OpenStudy (anonymous):

yeah that

OpenStudy (anonymous):

or \[x<3\] same thing

OpenStudy (anonymous):

So x has to be bigger than three?

OpenStudy (anonymous):

No wait

OpenStudy (anonymous):

x has to be less than three

OpenStudy (anonymous):

yes less than 3

OpenStudy (anonymous):

\(x<3\) and \(3>x\) say the same thing

OpenStudy (anonymous):

so would the set notation= {x E R | 3>x} ?

OpenStudy (anonymous):

set builder notation would look like \[\{x|x<3\}\]

OpenStudy (anonymous):

or what you wrote is fine

OpenStudy (anonymous):

Oh okay, thanks!

OpenStudy (anonymous):

yw

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