Please, explain me
I don't understand last line
me neither, it should be \(\large \left|\dfrac{4}{n+2}\right|\)
Thank you!! I feel like dummy when I can't understand how they get it !! ( from the book)
mostly a typo I hope :)
@ganeshie8 help me with this problem, please. Prove that the order of a permutation in \(S_n\) divides n! How to start?
Iis it not that order of permutation in S_n is n and n! = n*(n-1) *..... which shows it divides n!
But I don't think that problem is so simple like that
Woah! I don't understand the question... whats S_n ?
May be it is a set of n elements
Oh, It is set of Symmetry of set of n elements Ha!! I am so bad at explanation. X = {x1,x2,....,xn} Symmetry ({X}) denoted by \(S_n\)
Not sure I may not be useful here as idk abstract algebra
It says a much stronger statement : order of symmetric group of n elements itself is n!
That's good enough, thank you. One more thing: On the paper I attached, the right hand side of the fist line should be \(|\dfrac{-4}{n+2}|\) right?
signs shouldnt matter as absolute bars fixes them : |-4| = |4|
Ok, it is clear now. :)
If n> N can we assume that \(\dfrac {\sqrt n}{n+1}< \dfrac{\sqrt N}{N+1}\)
yes \(\large \dfrac{1}{n+1} \lt \dfrac{1}{n}\)
plugin n = 1
\(\large \dfrac{1}{1+1} \lt \dfrac{1}{1}\)
You mean I have to use induction to prove it before using the result to continue my stuff??
nope, its just a mind game... proof is not needed i think
1/2 < 1 what proof do u want for this ?
hmm
1/(n+1) < 1/n ofcourse presumably "n" is positive
I have to prove lim of a sequence =0, part of them is the expression above. Since it is a proving problem, every single line must be proved.
that is a lot of proving at some point something should be obvious without proof
@satellite73 but at least we have to have a logic to make a conclusion, right?
i feel it should be okay to use it without a proof, in limits proofs we use this all the time : \[\large \dfrac{1}{n-1} \lt \epsilon \implies \dfrac{1}{n}\lt \epsilon \] we can make conclusions like this in the back of head in proofs
its same as reasoning : \[\large 10 \lt a \implies 9 \lt a\]
Got you, thanks for the help,:)
np :D
Join our real-time social learning platform and learn together with your friends!