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Mathematics 10 Online
OpenStudy (anonymous):

A candidate is required to answer 6 out of 10 questions which are divided into two groups ,each containing 5 questions. he is not permitted to attempt more than four questions from either group.THe number of different ways in which the candidate can choose six questions

ganeshie8 (ganeshie8):

First, notice that since he can choose atmost 4 questions from one group, he needs to choose atleast 2 questions frome each group

ganeshie8 (ganeshie8):

That gives us 3 cases to work with : first group : 4 questions second group : 2 questions first group : 3 questions second group : 3 questions first group : 2 questions second group : 4 questions

ganeshie8 (ganeshie8):

for the first case : you can choose 4 questions from the available 5 questions in 5C4 ways you can choose 2 questions from the available 5 questions in 5C2 ways So the total number of ways of answering 4 questions from first group and 2 questions from second group would be : 5C4*5C2

ganeshie8 (ganeshie8):

see if you can work the remaining cases similarly

OpenStudy (anonymous):

ok thanks

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