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OpenStudy (anonymous):
\[4=\sqrt{q-2}\]?
OpenStudy (anonymous):
yeah
OpenStudy (anonymous):
I need help with this
OpenStudy (anonymous):
square to get
\[16=q-2\]
OpenStudy (anonymous):
when you square \(4\) you get \(16\) and when you square \(\sqrt{q-2}\) you get \(q-2\)
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OpenStudy (anonymous):
okay
OpenStudy (anonymous):
so is that all I need to do?
OpenStudy (anonymous):
if you want to solve
\[16=q-2\] for \(q\) add \(2\) to \(16\)
OpenStudy (anonymous):
so it would be 18=q?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
wow okay that was easy.
OpenStudy (anonymous):
lol ikr
OpenStudy (anonymous):
my answer choices are
A. sqrt 6
B. 36
C.3
D.6
OpenStudy (anonymous):
so 18=q isn't right
OpenStudy (anonymous):
it is definitely right
is the question exactly
\[4=\sqrt{q-2}\]
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OpenStudy (anonymous):
yes.
OpenStudy (anonymous):
can you post a screen shot?
OpenStudy (anonymous):
the check is easy
18 minus 2 is 16, the square root of 16 is 4
OpenStudy (anonymous):
how do I screen shot
OpenStudy (anonymous):
im on connexus
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OpenStudy (anonymous):
i don't know how to use your computer
i have a screen shot button on my keyboard
says "print screen"
OpenStudy (anonymous):
I have a button that says prt sc
OpenStudy (anonymous):
is that the same thing
OpenStudy (anonymous):
could the problem have really been
\[4=\sqrt{q}-2\]?
OpenStudy (anonymous):
yes.....
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OpenStudy (anonymous):
im sry I got mixed up
OpenStudy (anonymous):
then i guess the answer is different, because that is not the same as
\[4=\sqrt{q-2}\]
OpenStudy (anonymous):
\[4=\sqrt{q}-2\] add two to four, then square it
OpenStudy (anonymous):
so 64?
OpenStudy (anonymous):
no I think its 32
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OpenStudy (anonymous):
is it32?
OpenStudy (anonymous):
no
OpenStudy (anonymous):
six times six is not thirty two
OpenStudy (anonymous):
oh.
OpenStudy (anonymous):
oh I thought is was 8x8. but once I did 6x6 I got 36
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OpenStudy (anonymous):
yes good
btw eight times eight is sixty four, not thirty two
OpenStudy (anonymous):
yeah I was being stupid for a moment
OpenStudy (anonymous):
can you help me with 1 more?
OpenStudy (anonymous):
k
OpenStudy (anonymous):
y=sqrt 4x-4
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OpenStudy (anonymous):
|dw:1410450319289:dw|
OpenStudy (anonymous):
what is the question?
\[y=\sqrt{4x-4}\] is an equation, not a question
OpenStudy (anonymous):
it says what is the domain of the functoin
OpenStudy (anonymous):
ok that means, since you cannot take the square root of a negative number, that you are being asked to solve
\[4x-4\geq 0\] for \(x\) which only takes two steps
OpenStudy (anonymous):
okay. what are the 2 steps
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OpenStudy (anonymous):
add 4, divide by 4
OpenStudy (anonymous):
so I would ad 4+4=8
8/4
OpenStudy (anonymous):
no
\[4x-4\geq 0\\
4x\geq 4\\x\geq1\]
OpenStudy (anonymous):
[4x-4\geq 0\\
4x\geq 4\\x\geq1\] I don't see the thing but this