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Mathematics 8 Online
OpenStudy (anonymous):

4=sqrt q-2

OpenStudy (anonymous):

\[4=\sqrt{q-2}\]?

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

I need help with this

OpenStudy (anonymous):

square to get \[16=q-2\]

OpenStudy (anonymous):

when you square \(4\) you get \(16\) and when you square \(\sqrt{q-2}\) you get \(q-2\)

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

so is that all I need to do?

OpenStudy (anonymous):

if you want to solve \[16=q-2\] for \(q\) add \(2\) to \(16\)

OpenStudy (anonymous):

so it would be 18=q?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

wow okay that was easy.

OpenStudy (anonymous):

lol ikr

OpenStudy (anonymous):

my answer choices are A. sqrt 6 B. 36 C.3 D.6

OpenStudy (anonymous):

so 18=q isn't right

OpenStudy (anonymous):

it is definitely right is the question exactly \[4=\sqrt{q-2}\]

OpenStudy (anonymous):

yes.

OpenStudy (anonymous):

can you post a screen shot?

OpenStudy (anonymous):

the check is easy 18 minus 2 is 16, the square root of 16 is 4

OpenStudy (anonymous):

how do I screen shot

OpenStudy (anonymous):

im on connexus

OpenStudy (anonymous):

i don't know how to use your computer i have a screen shot button on my keyboard says "print screen"

OpenStudy (anonymous):

I have a button that says prt sc

OpenStudy (anonymous):

is that the same thing

OpenStudy (anonymous):

could the problem have really been \[4=\sqrt{q}-2\]?

OpenStudy (anonymous):

yes.....

OpenStudy (anonymous):

im sry I got mixed up

OpenStudy (anonymous):

then i guess the answer is different, because that is not the same as \[4=\sqrt{q-2}\]

OpenStudy (anonymous):

\[4=\sqrt{q}-2\] add two to four, then square it

OpenStudy (anonymous):

so 64?

OpenStudy (anonymous):

no I think its 32

OpenStudy (anonymous):

is it32?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

six times six is not thirty two

OpenStudy (anonymous):

oh.

OpenStudy (anonymous):

oh I thought is was 8x8. but once I did 6x6 I got 36

OpenStudy (anonymous):

yes good btw eight times eight is sixty four, not thirty two

OpenStudy (anonymous):

yeah I was being stupid for a moment

OpenStudy (anonymous):

can you help me with 1 more?

OpenStudy (anonymous):

k

OpenStudy (anonymous):

y=sqrt 4x-4

OpenStudy (anonymous):

|dw:1410450319289:dw|

OpenStudy (anonymous):

what is the question? \[y=\sqrt{4x-4}\] is an equation, not a question

OpenStudy (anonymous):

it says what is the domain of the functoin

OpenStudy (anonymous):

ok that means, since you cannot take the square root of a negative number, that you are being asked to solve \[4x-4\geq 0\] for \(x\) which only takes two steps

OpenStudy (anonymous):

okay. what are the 2 steps

OpenStudy (anonymous):

add 4, divide by 4

OpenStudy (anonymous):

so I would ad 4+4=8 8/4

OpenStudy (anonymous):

no \[4x-4\geq 0\\ 4x\geq 4\\x\geq1\]

OpenStudy (anonymous):

[4x-4\geq 0\\ 4x\geq 4\\x\geq1\] I don't see the thing but this

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