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Mathematics 22 Online
OpenStudy (darkbluechocobo):

The domain and range of the square root function below is: Domain: half open interval[1, ∞) and Range: half open interval(-∞, -1].

OpenStudy (darkbluechocobo):

ganeshie8 (ganeshie8):

what do you think

OpenStudy (darkbluechocobo):

false because that doesnt look like the points at all

ganeshie8 (ganeshie8):

why not, domain is all the x coordinates of graph, right ?

OpenStudy (darkbluechocobo):

but 1, infinite doesnt look right

ganeshie8 (ganeshie8):

Look at the graph, the only x coordinates for which the graph exists is after x=1

ganeshie8 (ganeshie8):

they cannot give you a graph that shows the sqrt function extending to infinity

ganeshie8 (ganeshie8):

it is assumed that the graph continues to the right forever

OpenStudy (darkbluechocobo):

well if that is the case then true o..o

ganeshie8 (ganeshie8):

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OpenStudy (darkbluechocobo):

buht with this one im confused because it looks like it starts at -5 buht it makes you choose 0 as starting point

OpenStudy (darkbluechocobo):

i know y is infinite

ganeshie8 (ganeshie8):

domain : x coordiantes (left and right) range : y coordinate (up and down)

ganeshie8 (ganeshie8):

you need to look vertically at the graph to figure out the range

ganeshie8 (ganeshie8):

Notice that the minimum `y` value of the graph is 0

ganeshie8 (ganeshie8):

yes ?

OpenStudy (darkbluechocobo):

So you look at it vertically?

ganeshie8 (ganeshie8):

and the graph is rising UP forever so the range would be [0, infinity)

ganeshie8 (ganeshie8):

yes for range you always look at it vertically

ganeshie8 (ganeshie8):

because range is all the possible y coordinates

OpenStudy (darkbluechocobo):

so since 0 ist he starting point it would be [0,infinite)

ganeshie8 (ganeshie8):

thats right !

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