Question

log (base3) x + 13 log (base3) x^4 =14

Answer 1

hope you know log(a) b +log(a) c = log(a) b*c

like a first step hope this will help you

Answer 2

and for second term

3log(a) b = log(a) b^3

Answer 3

so and you can rewriting the 14 like log(3) 3^14

because you know that log(3) 3 = 1

Answer 4

Yeah first i moved the 13 to get log (base 3) x^17, then multipled to get log (base3) [x(x^17)]

Answer 5

so (x^4)^13 not is equal x^17

Answer 6

so (x^a)^b = x^(a*b)

ok ?

Answer 7

so it should be 52?

Answer 8

yes

Answer 9

so when i combine them it would be log(base3) x^53= 14?

Answer 10

yes but how can you rewriting the 14 using log(3) ?

Answer 11

3^14= x^54? Im not sure.

Answer 12

why exponent 54 ?

Answer 13

52+1=53

Answer 14

i meant to write 53

Answer 15

yeah so it would be 4782969=x^53?

Answer 16

you have any choice ?

Answer 17

what do you mean?

Answer 18

what is the right result ?

Answer 19

i get 115911 when i do the 53rd root of the number which it says is wrong

Answer 20

you dont missed anything there in this exercise ? ,because this is the right way to solve it sure

Answer 21

nope im not missing anything