Question

help please

Answer 1

\[F(x)=8x+3\]\[F(x)=8(x-3)\]\[F(x)=8x-3\]\[F(x)=8(x+3)\]

Answer 2

which of the following is the function F(x) if
\[F ^{-1}(y)=\frac{ y }{ 8 }+3\]

Answer 3

@e.mccormick can you help me again please

Answer 4

@robtobey can you help?

Answer 5

Ah, they gave you the inverse. Know how to invert it again?

Answer 6

no i dont sadly

Answer 7

\(F ^{-1}(y)=\frac{ y }{ 8 }+3\)
becomes:
\(x=\frac{ y }{ 8 }+3\)

Now solve for y=bla

Answer 8

im lost

Answer 9

what dose the bla stand for?

Answer 10

I just put it there because until you solve it you won't know which equation it is.

When they say "solve for" know what it means?

Answer 11

no :(

Answer 12

OK. Let me do an example:

\(2x+4y-6=0\) Lets say I want that in Slope Intercept form: \(y=mx+b\). To do that, I solve for y.

\(2x+4y-6=0\)
\(2x+4y-6+6=0+6\)
\(2x+4y=6\)
\(2x-2x+4y=-2x+6\)
\(4y=-2x+6\)
\(4y/4=(-2x+6)/4\)
\(y=-2x/4+6/4\)
\(y=-1/2x+3/2\)

That is the sort of thing "solve for" means.

Answer 13

oh ok so what do i need to solve y

Answer 14

It is the reverse of PEMDAS. First, whatever was added you subtract, hatever was subtracted you add. Then whatever was multiplied you divide, etc. The goal is to get y alone on one side of the = and everything else on the other.

Answer 15

So, for this:

\(x=\frac{ y }{ 8 }+3\)

Something is added. That means you start by subtracting it from both sides of the equation. That keeps the equation balanced (equal.)