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herro
\[\Theta=\frac{ \pi }{ 3 }\] and the radius = 5 what is the arc length
5 cm*
\[s=r \theta \] formula for arc length. theta is in radians and r is the radius so plug in what you have
s=5(pi/3) = 5.2? or do i do something different with pi/3
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it is 5pi/3 and approximately 5.2
okay but see what im confused on is the format now http://gyazo.com/21b799b2b8d085814fb526da4f64a723 it would be the last one correct?
yes
thank you
you're very welcome
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a good thing to remember yoo is where that formula came from. a radian is the ratio of the arc length over the radius \[\theta=\frac{ s}{ r}\]
*too
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