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Mathematics 16 Online
OpenStudy (anonymous):

help

OpenStudy (anonymous):

herro

OpenStudy (anonymous):

\[\Theta=\frac{ \pi }{ 3 }\] and the radius = 5 what is the arc length

OpenStudy (anonymous):

5 cm*

OpenStudy (anonymous):

\[s=r \theta \] formula for arc length. theta is in radians and r is the radius so plug in what you have

OpenStudy (anonymous):

s=5(pi/3) = 5.2? or do i do something different with pi/3

OpenStudy (anonymous):

it is 5pi/3 and approximately 5.2

OpenStudy (anonymous):

okay but see what im confused on is the format now http://gyazo.com/21b799b2b8d085814fb526da4f64a723 it would be the last one correct?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

thank you

OpenStudy (anonymous):

you're very welcome

OpenStudy (anonymous):

a good thing to remember yoo is where that formula came from. a radian is the ratio of the arc length over the radius \[\theta=\frac{ s}{ r}\]

OpenStudy (anonymous):

*too

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