Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

Check my work, please During a visit to a primary care physician's office, the probability of having neither lab work nor referral to a specialist is 0.21. Of those coming to that office, the probability of having lab work is 0.41 and the probability of having a referral is 0.53. What is the probability of having both lab work and a referral?

OpenStudy (anonymous):

Let A :={x | x has lab work} --> P(A) = 0.41 B:= {x | x has referral} --> P(B) = 0.53 \(P(A\cap B)' = 0.21\)

OpenStudy (anonymous):

--> \(P (A \cap B ) = 0.78\), right?

ganeshie8 (ganeshie8):

0.78 looks very huge

OpenStudy (anonymous):

--> \(P (A\cup B) = 0.78\)

OpenStudy (anonymous):

\(P (A\cap B) = P(A) +P(B) - P( A\cup B) \\0.41+0.53-0.78=0.16\)

OpenStudy (anonymous):

Am I right?

OpenStudy (anonymous):

\[P(A'\cap B') =P(A\cup B)'= 0.21\]

ganeshie8 (ganeshie8):

\[\large P(A\cup B) = 1-P(A'\cap B') = 1-0.21 = 0.79\] right ?

ganeshie8 (ganeshie8):

the final answer should be 0.15 just pointing out an arithmetic error :P

OpenStudy (anonymous):

Thank you, I see my mistake now. :)

ganeshie8 (ganeshie8):

i would have done this using venn diagram to visualize but i agree manipulating like this without using venn diagrams is very important to logically see the relationship

ganeshie8 (ganeshie8):

|dw:1410484736912:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!