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OpenStudy (anonymous):
with no doubt l'hopital not allowed
OpenStudy (kkutie7):
\[\frac{sin(12x)}{sin(7x)}\]
here this is easier to look at
OpenStudy (anonymous):
\[\lim_{x\to 0}\frac{\sin(12x)}{\sin(7x)}\]
OpenStudy (anonymous):
Yes, but what is the correct answer? I keep getting 12/7. Not sure if this is right.
OpenStudy (anonymous):
what else could it be?
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OpenStudy (anonymous):
you want the math teacher way?
OpenStudy (anonymous):
I want the helpful way..
OpenStudy (anonymous):
the snap way is l'hopital but i will guess that you did not get there yet
the slow way is
\[\lim_{x\to 0}\frac{\sin(ax)}{\sin(bx)}=\frac{\sin(ax)}{ax}\frac{bx}{\sin(bx)}\frac{ax}{bx}\]
OpenStudy (anonymous):
this requires knowing that
\[\lim_{x\to 0}\frac{\sin(x)}{x}=1\] which you need
OpenStudy (anonymous):
Wow, never learned that, I know that, that is equal to one. thanks!
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OpenStudy (anonymous):
yw
geerky42 (geerky42):
That... That is very good approach... wow
I shed manly tear at the beauty of mathematics