Question

which statement shows a function?

Answer 1

just remember that a function will not have any 2 x values the same. They can have y values the same, just not the x ones

Answer 2

\[a)\left| x \right|+\left| y-1 \right|=1\]\[b)x^2+y^2=5\]\[c)e^\left| x \right|+e^y=2\]\[d)\left| x \right|+y^2-2y=0\]
I'm sure that b isn't a function.

Answer 3

@k142.can you help me?

Answer 4

@ganeshie8.can you help me?

Answer 5

How do you know b is not a function ?

Answer 6

\[1^2+(-2)^2=5\]\[1^2+2^2=5\]
(1,-2) and (1,2)
because a function can have y values the same, just not the x ones

Answer 7

That is correct.
You just need to extend the same logic to the other parts.
What about a ?

Answer 8

\[\left| 0 \right|+\left| 2-1 \right|=1\]\[\left| 0 \right|+\left| 0-1 \right|=1\]
(0,2) and (0,0)
so this isn't a function,either.

Answer 9

@ganeshie8.help,please.

Answer 10

\(d\) is also not a function since there is a \(y^2\) term so when you solve for \(y\), you will get two different values for \(y\)

Answer 11

\[\large \left| x \right|+y^2-2y=0 \implies (y-1)^2 = 1-|x|\]
\[\large \implies y-1 = \pm (1-|x|)\]