Question

If 35.5 mL of 0.23 M HCl is required to completely neutralize 20.0 mL of NH3, what is the concentration of the NH3 solution? Show all of the work needed to solve this problem.

HCl + NH3 yields NH4Cl

Answer 1

use
\[\large \bf V1 \times M1=V2 \times M2\]
where,V1=35.5 mL,M1=0.23 M and V2=20 mL

plug all the values in the formula and get your answer

Answer 2

understood? @Avenged7x

Answer 3

no.. what is m2?

Answer 4

M2 means second substance molarity which neutralise the other substance

Answer 5

understood? @Avenged7x