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Mathematics 17 Online
OpenStudy (anonymous):

help :) http://gyazo.com/6bb56de43b3148e111f1c9f0de262909

OpenStudy (e.mccormick):

Know what simialr means in math?

OpenStudy (anonymous):

yeah they aren't exactly congruent but similiar like a smaller version

OpenStudy (e.mccormick):

Yes, smaller or larger, but with a ratio to the sides. So if one was half as large as the other, you could half every measure to go from large to small or double every measure to go from small to large. In this case, you have 3 measures given. The ratio of two knowns, one on the large and one on the small, is the ratio between the two.

OpenStudy (e.mccormick):

So, you are given the radius on both. What is the ratio of the radii?

OpenStudy (anonymous):

the ratio is 5 of the bigger one

OpenStudy (anonymous):

no i mean 7* thats height 5

OpenStudy (anonymous):

and 4 is the ratio of the small one

OpenStudy (e.mccormick):

A ratio is somethng to something, so a:b or as a fraction, \(\dfrac{a}{b}\)

OpenStudy (anonymous):

oh im thinking of radius

OpenStudy (anonymous):

would it be 7/4 or 4/7

OpenStudy (e.mccormick):

That make sense because you are given the radius on both. So you want a ratio of the radii. Yes, either of those works. 7/4 is large/small 4/7 is small/large Now, you set up a ratio with the 5 and x that is in the same order. So if you do large/small then what is known on the large must be on to. If you do small/large then what is unknown must be on top. Either way, your choice, it will work.

OpenStudy (anonymous):

5/x and 7/4 do I then cross multiply?

OpenStudy (e.mccormick):

Any two matched measurements make the ratio. That means ALL the ratios are the same, or equal. And yes, that means: 5/x = 7/x So you cross multiply, solve for x.

OpenStudy (anonymous):

thank you very much!

OpenStudy (e.mccormick):

This works for any two similar shapes. In fact, sometimes you will get equations as the measurments. As long as you remember that similar means ratio of the matching parts you can set those up and solve them.

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