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Chemistry 15 Online
OpenStudy (anonymous):

chem

OpenStudy (anonymous):

i'm sorry i dont know how to do this :/ ask @aaronq maybe he knows how to do it.

OpenStudy (jfraser):

in order to find the order, you need to compare 2 different trials, where the concentration of A is held constant, but the concentration of B is changed. Then compare the 2 starting concentrations, and the resulting rates. For example, look at trials 1 and 2:

OpenStudy (jfraser):

when the concentration of B was changed from 0.020M to 0.010M, the time doubled. In other words, when the concentration of B is doubled, the reaction rate also doubles

OpenStudy (jfraser):

\[\frac{R_2}{R_1} = \frac{[B_2]}{[B_1]}^n\]

OpenStudy (anonymous):

is this correct @JFraser

OpenStudy (anonymous):

i propose you to read about kinetic of chemical reactions.

OpenStudy (anonymous):

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OpenStudy (anonymous):

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