Question

What is the derivative of (-)tanhsech(5x+2)

Answer 1

what is that -tanhx(sexh(5x+2)

Answer 2

yes

Answer 3

you wrote \(-tanh(sech(5x+2))\) it looked to me like this
make sure!

Answer 4

yes

Answer 5

so which one the first or the second? pls make sure

Answer 6

or do a snapshot of the problem so we are sure what we are doing

Answer 7

the second one

Answer 8

So it is the composition of the composition

Answer 9

First let's work on the outer functions and then go to the inner functions
okay
using the Chain rule!
do you know how to use Chain Rule?

Answer 10

yes

Answer 11

\(\frac{d}{dx}(f(g(x))=f'(g(x))g'(x)\)

Answer 12

let denote \(f(x)=-tanh(x),~~g(x)=sec(5x+2)\)

Answer 13

so we would have:
\(\frac{d}{dx}(-tanh(sech(5x+2))=-tanh'(sech(5x+2))\times sech'(5x+2)\)

Answer 14

now what is (tanh(x))'?

Answer 15

Do you know it?

Answer 16

sech^2x

Answer 17

correct! now instead of x we put sech(5x+2)

Answer 18

okay

Answer 19

??

Answer 20

ok... thank you so much sir

Answer 21

could you help with this
If I =
VR
, and V = 250volts and R = 50 ohms. Find the chandes in I resulting from an increase of I volt in V and an increase of 0.5 0hms in R. I decreasesv by

Answer 22

now you have to use Chain rule one more time with (sech(5x+2))'

Answer 23

well that's easy
find the initial current
find the new one then find the difference like the volume problem

Answer 24

ok sir

Answer 25

what about this sir?

Answer 26

Solve
lim(x)→(π)(x2−sinx)
. Find the limits

Answer 27

eh that's not clear!
can try writing it one more time?

Answer 28

limit as x tends to pi of (x^2 - sinx)

Answer 29

well that's easy no!
sinx is defined for any number on the real line (real numbers)
so just put pi into sin
and x^2 (in fact any polynomial you just plug in the number to find the limit)
because there are well defined every where

Answer 30

when the number that the the function is approaching is defined and is part of the domain
then the limit is easy! just replace in the number you are trying to approach

Answer 31

2π
1
π
0

Answer 32

again it is not clear

Answer 33

2pi
1
pi
0

Answer 34

you sure!
or make sure you wrote the function the right way

Answer 35

am soooo sure

Answer 36

So let me ask this again this what you trying to find its limit \(\lim_{x\rightarrow\pi}(x^2-sin(x))\)

Answer 37

?

Answer 38

very correct sir

Answer 39

in you option you should have \(\pi^2\)

Answer 40

what i have is
2π
1
π
0

Answer 41

2pi
1
pi
0

Answer 42

you know what post a snapshot of this problem okay!

Answer 43

something is not correct!

Answer 44

hey or you looking for limit of \(2x-sinx\) not \(x^2-sinx\)

Answer 45

will, i do not hv the app sir

Answer 46

if you have the homework on you computer you can you use screen print button

Answer 47

print screen button*

Answer 48

or if it is a physical paper use the camera of your phone

Answer 49

hey you still there, pls be quick i have to go
got bunch of homework to complete

Answer 50

did you get it?

Answer 51

hey the options given are not correct!
look at this graph and see what the function is approaching when x tends to pi
https://www.desmos.com/screenshot/a1sw2fvzcc

Answer 52

pi=3,14..... is between 2 and 4

Answer 53

well btw 3 and 4 actually

Answer 54

should be \(\pi^2\)

Answer 55

ok.... thanks so much. i hv to let you go do some other things..... will chat with you next time... God bless

Answer 56

bye

Answer 57

bye friend and my tutor

Answer 58

you are welcome^_^
make sure to tell your instructor that there is a mistake there

Answer 59

bye

Answer 60

yes sir