can you help me match these/@zimmah http://scde.mrooms.org/file.php/1738/Images/5.5HW_M1P.PNG
it's asking for login and password
do u see it now i uploaded it
heres the answers too it
\[\large \sqrt[3]{64} = \sqrt[3]{2*32}=\sqrt[3]{2*2*16}=\sqrt[3]{2^6}=4\]
the answers do not match the questions
hold rite quick hold up
\[\sqrt{(-2)^2}=2\]
heres the questions
heres the answers
to solve roots, you have to break the number under the root up in prime factors
\[\large \sqrt[5]{-243}\] so we have to split -243 up in prime factors. we begin by trying to divide by 2, which won't work because it's an odd number, so we try 3, which works, and makes 81 81 can again be divided by 3 to make 27 27 can again be divided by 3 to make 9 and 9 makes 3 so -243 = -3*3*3*3*3
can u match the questions with the answers like u did before because im still confused
\[\sqrt[5]{-3*3*3*3*3}\] there's a 3 in there 5 times, and since it's the 5th degree root we can therefore remove 4 of the 3's and put the 5th 3 in front. so we have \[3\sqrt[5]{-1}\]
still confused
so number 3 is question 6
\[\sqrt{2*2}=2 \] \[\large \sqrt[3]{2*2*2}=2\]
k i have that one how about the other ones
the bigger the root, the more of the same number you need to 'come out' of the root
i am not trying to feed you answers i'm trying to make you understand how it works
i am
first you divide the big number under the root into the smallest bits you can
than you count how many of the same number you have, and see if you have enough of any number to break free of the root
if you have the 5th root, you need 5 of the same number, if you have the 3rd root, you only need 3. etc.
so i would do=4096/4?
you divide by prime numbers always
k so im doing it rite
it's best to just go through prime numbers in order, starting with the smallest. so first 2, then 3, then 5, then 7, then 11, then 13, then 17 and you'll probably won't need any higher
well you can divide by 4 but that's basically dividing by 2 twice
so is the answer four cause i divied and got 1024
and then i counted
\[\large \sqrt[4]{-4096} = \sqrt[4]{4*1024}\]
oh and the - sign
but you can still keep dividing, it's still not in the smallest form
keep dividing until you can't divide any of the numbers under the root anymore
you can probably divide it a lot of times by 2
is it +13?
look how many times can you divide 4096 by 2?
2 times
really?
4
4096 / 2 = 2048 2048/2 = 1024 that's 2 times, but i guess we can do that about 10 more times or so
so its 2
.....
i'm done for today
=[
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