Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

Linear Algebra:

OpenStudy (anonymous):

Explain, if B = A intersects B, then \[B \subseteq A\] and conversely

OpenStudy (loser66):

--> \(B= B\cap A\) 1) \(B\subseteq (B\cap A) \) Let x \(\in B\) , x \(\in B\cap A\) = x \(\in B \) and x \(\in A\) which shows \(B\subseteq A\)

OpenStudy (loser66):

Visualize it by Venn. |dw:1410575646428:dw|

OpenStudy (anonymous):

How did you show, B is a sub set of (B intersection A) ?

OpenStudy (anonymous):

I understand that for X contained in B, X contained in B intersect A, then X is contained in A

OpenStudy (loser66):

\[B= B\cap A\] Means \[B\subseteq (B\cap A) ~~and~~ (B\cap A)\subseteq B\]

OpenStudy (loser66):

That's why on top I put --> , it means I prove from left to right, next you can use from right to left <--- , to prove "conversely"

OpenStudy (anonymous):

Conversely I would say, \[x \in B = BintersectionA\]?

OpenStudy (loser66):

conversely on this problem means if \(B\subseteq A\) then B = \(B \cap A\)

OpenStudy (anonymous):

Right so first I would say X in B and since B is a subset of A X in A and which means B = B intersect A ?

OpenStudy (anonymous):

for the conversely

OpenStudy (loser66):

yes, something like this, just add some more lines. |dw:1410576394383:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!