Linear Algebra:
Explain, if B = A intersects B, then \[B \subseteq A\] and conversely
--> \(B= B\cap A\) 1) \(B\subseteq (B\cap A) \) Let x \(\in B\) , x \(\in B\cap A\) = x \(\in B \) and x \(\in A\) which shows \(B\subseteq A\)
Visualize it by Venn. |dw:1410575646428:dw|
How did you show, B is a sub set of (B intersection A) ?
I understand that for X contained in B, X contained in B intersect A, then X is contained in A
\[B= B\cap A\] Means \[B\subseteq (B\cap A) ~~and~~ (B\cap A)\subseteq B\]
That's why on top I put --> , it means I prove from left to right, next you can use from right to left <--- , to prove "conversely"
Conversely I would say, \[x \in B = BintersectionA\]?
conversely on this problem means if \(B\subseteq A\) then B = \(B \cap A\)
Right so first I would say X in B and since B is a subset of A X in A and which means B = B intersect A ?
for the conversely
yes, something like this, just add some more lines. |dw:1410576394383:dw|
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