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Which of the following is a solution of z^6 = 64i? 2(cos105° + isin105°) 2(cos120° + isin120°) 2(cos135° + isin135°) 8(cos15° + isin15°)
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can you write "i" in the form of \(\cos \theta +i\sin \theta \) what value of theta will u take ?
\(z^6 = 64(\cos \theta +i\sin \theta ) \\ z =2 (cos (\theta/6) + i \sin (\theta/6) )\) using DeMovire's Theorem, You only need theta :)
Divide the theta by 6, and you will get your angle :)
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