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Mathematics 8 Online
OpenStudy (anonymous):

How do you prove that a function is/isn't differentiable at its endpoints?

OpenStudy (anonymous):

The question that I am doing only requires identifying it graphically

OpenStudy (anonymous):

But I would also like to know how to do it with limits, or however they expect me to do it in calculus

OpenStudy (precal):

I would use the Theorem about Differentiability. If the function is differentiable then the function is continuous.

OpenStudy (anonymous):

Do you mean the other way? If a function is continuous then it is differentiable?

OpenStudy (precal):

But you can't use the converse of it ie If a function is continuous then it is differentiable. This is not a true statement.

OpenStudy (anonymous):

My issue is that i don't know if the function is differentiable. I am supposed to identify which points the function is differentiable on in a closed interval

OpenStudy (precal):

attach the graph

OpenStudy (precal):

draw slopes on the graph. If you can draw the slopes then that is your derivative

OpenStudy (anonymous):

|dw:1410623917120:dw|

OpenStudy (anonymous):

The function is continuous at its endpoints

OpenStudy (precal):

Then this particular graph is differentiable but the endpoints look like they have vertical tangents

OpenStudy (anonymous):

They aren't. They don't look that extreme in the book. My question is how do you know that it is differentiable for its domain?

OpenStudy (precal):

maybe vertical asymptotes

OpenStudy (precal):

Usually the endpoints are not included in the theorems about differentiability

OpenStudy (anonymous):

Thats a problem

OpenStudy (precal):

if the endpoints are not included, it is differentiable

OpenStudy (anonymous):

The endpoints are included in the problem

OpenStudy (precal):

Are you looking at a particular theorem?

OpenStudy (anonymous):

However I am supposed to solve the rpobk

OpenStudy (anonymous):

*problem

OpenStudy (precal):

@dumbcow

OpenStudy (precal):

let's see if dumbcow can help us

OpenStudy (anonymous):

Ok, thanks

OpenStudy (dumbcow):

hmm well as long as its continuous and smooth the function is differentiable at all points if there is a sharp curve where its not smooth like an absolute value, then its not differentiable

OpenStudy (anonymous):

What if the endpoints aren't continuous?

OpenStudy (dumbcow):

is the function defined at the endpoint?

OpenStudy (anonymous):

On this particular problem, it is continuous.

OpenStudy (dumbcow):

for example, say function is x^2 for -1<=x<=2 i know that derivative is 2x so the slope of tangent at endpoints are -2 and 4 thus since the endpoints are defined and lie along a smooth curve, the endpoints are differentiable

OpenStudy (anonymous):

They don't give us the function, they only give us the domain

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