I have a question in regards to number 6
@precal
What book is this from?
Calculus: Graphical, Numerical, Algebraic
What page?
114
A. All points in [-2,3] B) none c) none
Yes
I know the answer, but idk why
btw not my favorite book so just like dumb cow said, yes you can take the derivative of the entire graph
Well give it a week or so, some math concepts need to be developed and this is one of them
Lol we move so quickly that we can't
Im in BC
still Calculus is a journey
@amistre64
is it a long question? i cant open the attachment
Well it involves a graph
can you get a screenshot? or a pic?
I can try to draw it
that might work :)
Ok
you draw nice lol
xD
now, it asking by looking at the graph for 3 conditions that may fit. right?
Yes
tell me what your ideas for the defnition of coninuity, and differentiability are.
typos not withstanding of course
Well my book kind of says a continuous function is one that can be drawn in one stroke, without lifting the pencil up. Its hard for me to explain. It says for a function to be differentiable at a point x means that it has a derivative at x
and problem 6, can it be drawn without lifting a pencil?
Yes
But that is only for continuity. Idk how to determine if it is differentiable at its endpoints
That was my big question
picture 2 ants, with rulers glued to their backs ... crawling along the curve one starts at one end, the other at other end.
the rulers define the slope of the curve at any point that an ant is at. if there is any point that the ants can approach and meet at, such that the slope shown is the same, then its differentiable .... if thier slopes are not the same, then its not.
does that make any sense?
Yes. The endpoints.
the end points are where the ants would start at. now, if one ant doesnt move, and the other ant walks to the other end of the curve, the slopes of both ants are equal. an endpoint can only be defined by a one sided limit. but this may be author specific
in general, smooth flowing curves are differentiable. things with corners and cusps, and broken lines are not
So as long as the endpoints are continuous, it is differentiable there?
differentiable has to do with limits, and limits dont care about if a point exists or not.
think of limits like a map, the map tells you to cross the bridge, but when you look ahead of you on the real road ... the bridge is out.
the limit is where the bridge would be, regardless of if there is a brdige actually there or not
Ok, so how do you know if it is differentiable with a one sided limit?
you reach the end of your domain, therefore the limit can only be one sided.
Ok, so how would I do it in this example?
Like how do you set that up? How of you know if it is differentiable or not based on the limit?
the walking ants is the best way i know to describe it without delving into any mathing of a function that is not 'defined'
5 and 6 are the same 'type' of problem
I know. I didn't know why 5 was differential at its endpoints either.
notice that in number 5, the slope of the line is the same regardless of where you are at
as you get closer and closer to an endpoint, can you tell what the slope of the line is?
Yes
But that is always the case
for endpoints, yes
the issue is when we are in between the end points
So a function is always differential at its endpoints?
a graph with a limited domain has distinct ends, and as such is always differentiable at the endpoints.
Ok, so as long as it has a restricted domain, and doesn't have any discontinuities it is differential at its endpoints?
limits must be the same when approached from all possible directions/paths. an endpoint of a curve has only one path, agreed?
Yes. A one sided limit
one sided because thats the only way to get there ....
right
lets take a function x/x^2, from 0<x<3 are we differentiable at the end points?
err, lets do x^2/x instead lol
lol. I have no idea
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