Question

solve = e^x ln(x + 1/2) = 0
i know the solution is 1/2 but i have no idea how they got there. i keep getting 1/4. what i did was this:
e^x ln(x + 1/2)= log e (x) . Log e ( x+ 1/2)=
Log e (2x + 1/2)
(2x + 1/2) = 1 (because e^1= 0)
X= 1/4

Answer 1

e^x * ln(x + 1/2) = 0
Either e^x = 0 OR ln(x+1/2) = 0 OR Both = 0
e^x approaches zero as x-> - infinity but never attains zero.

So ln(x+1/2) = 0 which implies x + 1/2 = 1 or x = 1/2 (because log(1) = 0)

Answer 2

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