help me with mean and population standard distribution. WILL MEDAL AND FAN
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OpenStudy (jessicawade):
Calculate the mean and the population standard deviation for the data set, rounded to thousandths. {2, 3, 5, 0, 3, 2, 1, 1, 5, 7, 8, 5, 3}
OpenStudy (anonymous):
mean=\[\mu=\frac{2+3+5+0+3+2+1+1+5+7+8+5+3}{number of elements=13}\]=\[\frac{45}{13}\]
sd =\[\sqrt{var} \] = \[\sqrt{|each number - mean|^2} \] =\[\sqrt{\frac{{(|2-\mu|^2+|3-\mu|^2+|5-\mu|^2+|0-\mu|^2+|3-\mu|^2+|2-\mu|^2+|1-\mu|^2+|1-\mu|^2+|5-\mu|^2+|7-\mu|^2+|8-\mu|^2+|5-\mu|^2+|3-\mu|^2)}}{((13-1)}}\]=\[5\cdot\sqrt{\frac{3}{13}}\]
OpenStudy (jessicawade):
what lol
OpenStudy (jessicawade):
you lost me at var i havnt learned that one yet
OpenStudy (jessicawade):
the mean is 3.46
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OpenStudy (jessicawade):
@Hero
OpenStudy (jessicawade):
@hartnn
OpenStudy (jessicawade):
@bakur
OpenStudy (anonymous):
313−−−√
OpenStudy (jessicawade):
whats 313?
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OpenStudy (jessicawade):
@jmatthews4929
OpenStudy (anonymous):
yes, @jassicawade. \[45/13=3.46\],
var = variance which is the how far each item in the population is to the mean \[\mu\], it is also defined as : average squared deviation from the mean.