Suppose a force of 20 N is required to stretch and hold a spring 0.4 m from its equilibrium position (0). I found k constant to be 50 and part b required using integration on 0 to -0.3 for spring compression on the and I found the work to be 2.25 J. Here's part c and d...

c) does it take twice as much work to compress the spring 0.6 meters from equilibrium as it does to compress 0.3 meters from equilibrium?

d)Does it take twice as much force to compress the spring 0.6 meters from equilibrium as it does to compress 0.3 meters from equilibrium?

Question

Suppose a force of 20 N is required to stretch and hold a spring 0.4 m from its equilibrium position (0). I found k constant to be 50 and part b required using integration on 0 to -0.3 for spring compression on the and I found the work to be 2.25 J. Here's part c and d...

c) does it take twice as much work to compress the spring 0.6 meters from equilibrium as it does to compress 0.3 meters from equilibrium?

d)Does it take twice as much force to compress the spring 0.6 meters from equilibrium as it does to compress 0.3 meters from equilibrium?

anonymous · Answer

not sure what to do here :)

anonymous · Answer

Relax, mate, I'm here.

anonymous · Answer

do i just integrate the 0 to -0.6 with the 50x then compare?

anonymous · Answer

i got the inegration for 0 to -0.6 to be 9 J and then dividing 9 by 2.25 J i get 4 times as much work required which i think is right because its more than twice the work

anonymous · Answer

I should think it's right. Too tired to do the calculations right now. Long day.

anonymous · Answer

oh okay :/ i have no clue about d though

anonymous · Answer

Ah. Remember that work = force * distance moved in a direction. Use that.

anonymous · Answer

Displacement, rather than distance.

anonymous · Answer

so 4 times as much work is right for part c?

anonymous · Answer

Can it wait till the morning?

anonymous · Answer

yea :)

anonymous · Answer

See you in the morning then! Lol.