OpenStudy (anonymous):

Help please.

3 years ago
OpenStudy (anonymous):

\[|2x+4|=(5x+1)-2\]

3 years ago
OpenStudy (anonymous):

First case: 2x + 4 = (5x +1) -2 7x = 5 x = 5/7 Second case: 2x + 4 = (-5x -1) + 2 7x = -3 x = -3/7

3 years ago
OpenStudy (anonymous):

The (5x+1) is not inside modulus right?

3 years ago
OpenStudy (anonymous):

These are the multiple choice answers.. A. { } B. {5/3} C. {-1, 5/3} D. {1/3, 5/3, -1}

3 years ago
OpenStudy (anonymous):

@M4thM1nd

3 years ago
OpenStudy (anonymous):

the (5x+1) is inside a modulus?

3 years ago
OpenStudy (anonymous):

I dont know what that means..

3 years ago
OpenStudy (anonymous):

it is not this you want to solve right? |2x+4|=|5x+1|−2

3 years ago
OpenStudy (anonymous):

No

3 years ago
OpenStudy (anonymous):

(5x+1) is only like this

3 years ago
OpenStudy (anonymous):

oh sorry i did a mistake

3 years ago
OpenStudy (anonymous):

First case: 2x + 4 = (5x +1) -2 3x = 5 x = 5/3 Second case: 2x + 4 = (-5x -1) + 2 7x = -3 x = -3/7

3 years ago
OpenStudy (anonymous):

as the second one is not a valid solution, teh answer is B

3 years ago
OpenStudy (anonymous):

{5/3}

3 years ago
OpenStudy (anonymous):

you sure?

3 years ago
OpenStudy (anonymous):

Yep

3 years ago
OpenStudy (anonymous):

Thanks.

3 years ago
OpenStudy (anonymous):

do you understand why the second solution is not valid?

3 years ago
OpenStudy (anonymous):

As we have |2x+4|=(5x+1)-2 (5x+1)-2 >=0 5x >= 1 x >= 1/5 The second solution is x = -3/7 which is less than 1/5 and that is why this solution is not valid

3 years ago
OpenStudy (anonymous):

thanks

3 years ago