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OpenStudy (anonymous):
\[|2x+4|=(5x+1)-2\]
OpenStudy (anonymous):
First case:
2x + 4 = (5x +1) -2
7x = 5
x = 5/7
Second case:
2x + 4 = (-5x -1) + 2
7x = -3
x = -3/7
OpenStudy (anonymous):
The (5x+1) is not inside modulus right?
OpenStudy (anonymous):
These are the multiple choice answers..
A. { }
B. {5/3}
C. {-1, 5/3}
D. {1/3, 5/3, -1}
OpenStudy (anonymous):
@M4thM1nd
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OpenStudy (anonymous):
the (5x+1) is inside a modulus?
OpenStudy (anonymous):
I dont know what that means..
OpenStudy (anonymous):
it is not this you want to solve right? |2x+4|=|5x+1|−2
OpenStudy (anonymous):
No
OpenStudy (anonymous):
(5x+1) is only like this
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OpenStudy (anonymous):
oh sorry i did a mistake
OpenStudy (anonymous):
First case:
2x + 4 = (5x +1) -2
3x = 5
x = 5/3
Second case:
2x + 4 = (-5x -1) + 2
7x = -3
x = -3/7
OpenStudy (anonymous):
as the second one is not a valid solution, teh answer is B
OpenStudy (anonymous):
{5/3}
OpenStudy (anonymous):
you sure?
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OpenStudy (anonymous):
Yep
OpenStudy (anonymous):
Thanks.
OpenStudy (anonymous):
do you understand why the second solution is not valid?
OpenStudy (anonymous):
As we have |2x+4|=(5x+1)-2
(5x+1)-2 >=0
5x >= 1
x >= 1/5
The second solution is x = -3/7 which is less than 1/5 and that is why this solution is not valid