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please solve using natural log: 5^x-1(times by) 3^x+2=10
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well if you take the log of each you get \[\ln(5^{x -1} \times 3^{x + 2}) = \ln(10)\] then applying the log laws for multiplication and powers you get \[(x -1)\ln(5) + (x + 2) \ln(3) = \ln(10)\] which becomes \[x(\ln(5) + \ln(3)) - \ln(5) + 2\ln(3) = \ln(10)\] so it simplifies to \[x(\ln(5) + \ln(3)) = \ln(10) + \ln(5) - \ln(3)\] now just solve for x
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