Question

Please, check.

Answer 1

@ganeshie8

Answer 2

How did you get your absolute value?

Answer 3

looks good to me !

\[\large \dfrac{5}{2n^2} \lt \dfrac{5}{n^2} \lt \dfrac{5}{n}\]

you're assuming \(\large n\gt 0\), right ?

Answer 4

the limit show n--> infinitive

Answer 5

so that n >0

Answer 6

@Deepolisnoob |-5|=5

Answer 7

--> | - the wholething| = the whole thing

Answer 8

Anything in absolute values turns positive...I'm asking how was the absolute value included because you started with parenthesis

Answer 9

oh, that comes from definition of limit

Answer 10

It says \(lim_{n\rightarrow \infty} a_n =L\) if \(|a_n-L|<\varepsilon \)

Answer 11

Thank you for the help. :)