Hey, to find the limits of interval for this problem, would I have to draw out the graph haha .

Question

Hey, to find the limits of interval for this problem, would I have to draw out the graph haha >.<? r=2(1+cos theta) even though it already looks as if it's 0<= theta < = 2 pi

astrophysics · Answer

@ganeshie8 Last question haha, I'll give you a break afterwards...for a while ;)

astrophysics · Answer

Find the exact length of the polar curve is the question 
$$r=2(1+\cos \theta)$$

astrophysics · Answer

Just the limits of interval I'm worried about as it wasn't given on this one.

ganeshie8 · Answer

0->2pi looks good to me 

by symmetry, finding the length in 0->pi and multiplying by 2 will also work

astrophysics · Answer

Alright, that seems to work, was tired of drawing graphs haha. But for symmetry you would have to know at least the generic look of the function?

ganeshie8 · Answer

$\large r(\theta) = r(-\theta) \implies   $ the graph is symmetrical about x axis

astrophysics · Answer

Right! I just did a question similar to that a while back, thanks!

ganeshie8 · Answer

because, r will be having same length for both $\large \theta $ and $\large -\theta $

ganeshie8 · Answer

but symmetry won't reduce the complexity of problem here i guess

astrophysics · Answer

Yeah, here is how it looks http://puu.sh/by8AA/e9c24ab899.png