Question

Calculate the amount of heat transferred when 550 grams of water warms from an initial temperature of 4.0 ºC to a final temperature of 25.0 ºC. The specific heat capacity of liquid water is 4.184 J/g ºC. Please express you answer as a number in units of kJ, which is already provided after the answer box, and be careful about the sign (is the answer a positive or negative number?) since that shows the direction of heat flow.

Answer 1

I think the answer should be 550 * 21 * 4.184 but it is marked wrong Why ?

Answer 2

\[Q _{H20}= 4.184 J/g ºC \times 550g \times 21.0 ºC = xxx J/1000= xxx Kj (positive)\]

Answer 3

with that equation you get joules.

1KJ= 10E+3 J

Answer 4

So the answer would be 48325.2 / 1000 = 4.83252 Kj ?

Answer 5

it will be 48.3 KJ.

Answer 6

Thanks !