Question

Is f(x)= x^-2 an even function? And why?

Answer 1

If a function is even, then \(f(-x)=f(x)\). That is:
Check is the following true?:
\((-x)^{-2}=x^{-2}\) ?

Answer 2

Thanks
What about f(x): 1- ^3radical x?

Answer 3

\(f(x)=1-\sqrt[3]{x}\) ?

Answer 4

regardless of your function though, to check if it's even, you always check if the relation: \(f(-x) = f(x)\) is true.. that is, if you substitute x with "-x", do you get the same function again?

Answer 5

Ok, its odd

Answer 6

Thanks

Answer 7

your welcome .. but becareful.. if a funtion is not even, it doesn't mean it's odd

Answer 8

function*

Answer 9

Just as an example, \(f(x)=x^3\) is odd since \(f(-x)=-f(x)\)
\((-x)^3=-x^3\) is true

But \(f(x)=1-x^3\) is not odd since \(f(-x)=1-(-x)^3=1+x^3\ne-(1-x^3)\)

Answer 10

Ok yea i know! But how does it look graphed?

Answer 11

How do input in my calc?

Answer 12

http://www.wolframalpha.com/input/?i=1-x%5E%281%2F3%29&a=%5E_Real

Answer 13

Oh I am not sure. I never had a graphing calculator so I don't know the inputs.