Question

help

http://gyazo.com/57a8b898e6c87d19ea62a481972a5833

Answer 1

You must be on the probabilities chapter. I don't blame you, it is kinda tricky and I've made lots of mistakes in this chapter. Anyways, let's solve this problem.

Now you have two events happening here, one is the toss of the coin, and the other is the roll of the die. These events are not linked or dependent upon each other.

So, case 1) If you get a heads

The probability of getting a heads is \[0.5\] since a coin has two sides, and heads is one side. so 1/2.

Case 2 ) Rolling a 2
A dice has 6 sides. One side only contains a 2. Hence your probability here is
\[\frac{1}{6}\]

Add the two together and your total probability is \[\frac{4}{6}\]

But we're not done yet. What if you get 2 AND a heads? In the case the questions terms are null since it only asks for one thing OR the other, not both of them together.

Calculate the probability of both heads and 2 occurring together like so..
\[\frac{1}{6} \times \frac{1}{2} = \frac{1}{12} \]
Subtract the answer from the probability we calculated above..
\[\frac{8}{12}-\frac{1}{12} = \frac{7}{12}\]

Which should give you your answer.

Answer 2

so for the question 4/6 is my answer since its not asking for the AND part? and simplified that would be 2/3 yes because thats one of my options 7/12 isn't