Medal awarded can someone please help me on 20., 22, and 26. For 20 I got 3 as my answer but i'm not 100% sure and on 22 and 26 I have no clue how to solve
for #20, you substitute the values of x,y&z to the expression
i got 4 square root of 27+56-2 I used pemdas and got 4 square root of 81 which is 3
that's correct
now proceed to #22. substitute the values
(3*4)^2*-1 I get 12^-2
yes. now what happens to a number raised to a power of a negative number?
1/12^2
1/144
yep
for 26 I looked at the previous problem we solved, I subtracted 48-3 which is 45 the only thing was when I was trying to find a number raised to the 4th power it didn't turn out to be 45
the previous one involves multiplication that's why it's okay but since this involves subtraction, your answer is invalid
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12*4
the square root of 4 is 2
is that your answer? well think about it, is 4 having a perfect "4th root"? think it again
try to think of another factor
16 and 3
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