Question

Solve the following system of equations:

2x - y + z = -3
2x + 2y + 3z = 2
3x - 3y - z = -4

Answer 1

Do you know how to do Matrices?

Answer 2

no @ChrisTopher987654321

Answer 3

I'd go on to the Khan academy website and learn that. Because without it you wouldn't have a structured way of doing it.

Answer 4

you may apply elimination and substitution method

Answer 5

I tried that andkept on messingup @shinalcantara

Answer 6

Here the knanacademy video that will help you
https://www.khanacademy.org/math/algebra/systems-of-eq-and-ineq/fancier-systems/v/systems-of-three-variables

Answer 7

Here's*

Answer 8

tnx @faith2012

Answer 9

You're welcome! I hope it'll help you.

Answer 10

as long as the number of unknowns is equal to the number of equations, you'll be able to get the values using elimination and substitution method.. though you may be able to answer this just by inputting all the coefficients to the calculator using MODE 5, 2 of your fx-991ES PLUS calculator, you have to know the basic.. :)

Answer 11

2x-y+z=-3 --- eq'n 1
2x+2y+3z=2 ----eq'n 2
3x-3y-z=-4 ------eq'n 3

add eq'ns 1& 3 you'll get
5x-4y=-7 -- ---let this be eq'n 4

rearrange eq'n 3 such that 'z' would have a value in terms of x & y
z = 4+3x-3y ------eq'n 5

substitute eq'n 5 to eq'n 2
2x+2y+3(4+3x-3y)=2
2x+2y+12+9x-9y=2
11x-7y=-10 -----eq'n 6

equate eq'ns 4 & 6 and multiply eqn 4 with 7 and eqn 6 with 4
you'll have:
(5x-4y=-7)*7 ----- 35x-28y=-49 ---eq'n 7
(11x-7y=-10)*4 44x-28y=-40 ---eq'n 8

subtract eqn 7 from eqn 8
9x=9
x=1

substitute to eq'n 4
5x-4y=-7
5(1)-4y=-7
4y=12
y=3

substitute to eqn 5
z=4+3(1)-3(3)
z=-2