Question

PLEASE HELP!!!

If 90° < θ < 180° and cotθ = -1/3, then cscθ = _____.

√7/3
√10/3
2√2/3
5/3

Answer 1

use the pythagorean formula
\(\large \csc^2 \theta = 1+ \cot ^2 \theta \)

Answer 2

then take square root to get csc theta

Answer 3

would it be 2√2/3??

Answer 4

1+1/9
10/9

how did u get that ?

Answer 5

i think i had a miscalculation!

Answer 6

ok, do it again and verify your new answer :)

Answer 7

i got squareroot10/3!

Answer 8

and you're \(\large \checkmark \) :)

Answer 9

@hartnn do you mind checking if my answer is correct for this question??

Position vectors u and v have terminal points of (-6, 3) and (4, -2), respectively. Find the resulting terminal point of 2v - u.



(2, -7)

(2, 1)

(14, -7)

(14, 1) <<< i got this!(:

Answer 10

14 is correct

Answer 11

2(-2) -3 = .. ?

Answer 12

omg im so dumb haha thank you again (: im doing a review for trig right now! Could i ask you more questions??

Answer 13

sure :)

Answer 14

If θ is an angle in standard position that passes through (3, 4), find sin2θ.



2/5

4/5

8/5

24/25 << i got this (:

Answer 15

@hartnn

Answer 16

2 (3/5) (4/5) = 24/25
you're correct :)

Answer 17

horray! You are helping me tons right now! (:

Answer 18

always happy to help ^_^

Answer 19

how would i solve this??

If cos2 x + 2cosx - 2 = 0, then cosx = _____.



-1 ±√3

1 ±√3

±√3

1

Answer 20

@hartnn !

A triangular lot bounded by three streets has a length of 300 feet on one street, 200 feet on the second, and 120 feet on the third. The smallest angle formed by the streets is 30°. Find the area of the lot.



6,000 ft2

9,000 ft2 <<< i got this!

15,000 ft2

30,000 ft2

Answer 21

how did u calculate area ?

Answer 22

Area = 1/2 * 300 * 75 = 11,250 sq. ft
i kinda rounded it to the closest answer;; :P

Answer 23

sorry, not so clear with the question...
area of triangle with sides,
200, 300, 120 will be 8049.22

Answer 24

i know right?? so should i just round it to 9,000ft^2??

Answer 25

is there any other info. or diagram with it ?
else i would also go with 9000 ...

Answer 26

oh okay!
how would i solve this??

If cos2 x + 2cosx - 2 = 0, then cosx = _____.



-1 plusminus squareroot3

1 plusminus squareroot3

plusminus squareroot3

1

Answer 27

is it cos 2x or
cos^2 x ?

Answer 28

cos^2x!

Answer 29

then its a quadratic in cos x
answer would be same as
x^2+2x-2=0

Answer 30

can you solve that quadratic ?

Answer 31

x=-1-√3??

Answer 32

is the answer -1 plusminus squareroot3
??

Answer 33

yes :)

Answer 34

θ is in standard position, and the terminal side passes through the point (3, -5).

Find sinθ.



-5sqrt31/31

-5sqrt34/34 << ??

-3/5

-4/5