Question

What is the 32nd term of the arithmetic sequence where a1 = −32 and a9 = −120?

Answer 1

Do you know how to get the formula?

Answer 2

I am lost I don't remember

Answer 3

an = a1 + (n-1)d

Answer 4

a1 is the first term, d is the difference, and n is the nth term.

Answer 5

-120=-32+(n-1) d

Answer 6

Good job!

Answer 7

wat do I do after that

Answer 8

You would put the first term in as "n"

Answer 9

So it would actually be a1+(-32-1)d=-120

Answer 10

Can you do the math, please?

Answer 11

but a1 =-32 so what do u mean

Answer 12

We're trying to figure out d first

Answer 13

a1-33d= a9
a1-a9=33d
That's when you plug in the numbers.

Answer 14

(-32)-(-120)=33d
-32+120=33d
88=33d
8/3 = d

Answer 15

Now we have d. So we use the formula: an=a1(n-1)d

Answer 16

a32=(-32)(32-1)8/3
Can you do the math?

Answer 17

Let's see if we get the same answer.