Question

minimum value of a quadratic is
-d/4a or D/4a

Answer 1

what are d,D ?

Answer 2

Discriminant, obviosly

Answer 3

both ?

Answer 4

Now ,yes

Answer 5

you mean D/4a or -D/4a ?

Answer 6

ok

Answer 7

\[\huge \left| d \right|=\left| D \right|\]

Answer 8

y = ax^2+bx+c

y' = 2ax +b
y'=0 =2ax+b

x= -b/2a

plug this in y

Answer 9

your a is positive or negative ?

Answer 10

does it matter

Answer 11

i mean i am asking
y co-oridinate of vertex , = minimum value

Answer 12

for
y = ax^2 +bx+c
min value is c-b^2/4a = D/4a

Answer 13

for
y = -ax^2 +bx+c
min value is -c+b^2/4a =- D/4a

Answer 14

oh

Answer 15

D/4a

Answer 16

my a is positive

Answer 17

sorry its reverse

Answer 18

-D/4a

Answer 19

for
y = ax^2 +bx+c
min value is c-b^2/4a = -D/4a

Answer 20

infact, irrespective of the value of a

Answer 21

always
-D/4a

Answer 22

that's what i was asking actually for
hehe

Answer 23

:P