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If mx^2 -9mx + 5m +1 >0 for all x and x belongs to R , then m lies in the interval
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m should not be negative. Can you please re-confirm the answer ?
sorry (0 , 4/ 61 )
hmm. so your polynomial p(x) > 0 for all x in R. Which means 2 things : 1) Graph of the curve lies completely above x axis , which further implies co-efficient of x^2 should be greater than 0. 2) Discriminant should be less than 0. Use the above facts and take the intersection of both the sets.
m>0 m< 4/61
(0, 4/61 ) thank u
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glad to help. ^^
y=61m^2-4m is a parabola that is open upwards when the zeros m=0 and m=4/61 So that would look like |dw:1410713378280:dw| (ugly parabola) But we can see from this graph that y>0 when m<0 or m>4/61
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