Question

Solve the following system of equations using elimination.
3x + 2y = 10
x + y = 4

Answer 1

A: x = 2, y = 2
B: x = -2, y = 2
C: x = -2, y = -2
D: x = 2, = -2

Answer 2

ok
you need to alter one of the equations so that you can elimante one of the variables
so it we multiply the second equation by -2 we can eliminate y
x + y = 4 multiply each term by -2 gives

-2x - 2y = -8 now add the first equation:
add 3x + 2y = 10

x + 0 = 2

x = 2

now plug x = 2 into the equation x +y = 4 and you get the value of y

Answer 3

ok can you find the value of y

put x = 2 in x+ y = 4

so
2 + y = 4

Answer 4

y = ?

Answer 5

2 + y = 4
-2 -2

y = 2

Answer 6

so the correct option is A

Answer 7

thanks coming with more

Answer 8

Which is a solution to the system: y > –4 and y < –1?
Select one:
a. (5,-4)
b. (0,–1)
c. Both A and B
d. Neither A or B

Answer 9

The point (5,-3) is a solution of the system:
y < 5x+3
y> 2x-4
Select one:
True
False

Answer 10

for the last one put x=5 and y = -3 into the 2 inequalities ans see if they fit.
first one

-3 < 5(5)+ 3
-3 < 28 True

now you try the second one

Answer 11

the previous one - answer is d

Answer 12

Which ordered pair satisfies the system?

Select one:
a. (0, 0)
b. (–2, 0)
c. (1, 5)
d. (4, 2)

Answer 13

@cwrw238

Answer 14

@cwrw238

Answer 15

(-2,0)