A horse canters away from its trainer in a straight line, moving 150 m away in 18.0 s. It then turns abruptly and gallops halfway back in 5.3 s. (b) Calculate its average velocity for the entire trip, using "away from the trainer" as the positive direction
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OpenStudy (micheletheresam):
@ProfBrainstorm :)))))
OpenStudy (micheletheresam):
I got the first part right yeeyee!!!! But idk about this and what's the formula?
OpenStudy (anonymous):
what did they ask for in the first part ?
OpenStudy (micheletheresam):
average speed
OpenStudy (micheletheresam):
It's was 9.66 m/s
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OpenStudy (anonymous):
ok, the average velocity is given by the net displacement from the starting point divided by the total time (I think)
OpenStudy (micheletheresam):
75/12.7??
OpenStudy (anonymous):
75 is right for the displacement, but it still took the total time, time still adds
OpenStudy (micheletheresam):
75/23.3?
OpenStudy (anonymous):
yes, i think that's what they're asking for
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