Question

Molarity of standardized NaOH solution is 0.1012
final buret reading, mL IS 31.21
INITIAL buret reading, mL IS 15.72
VOLUME OF TITRANT, mL is 15.49
Moles of NaOH used is 1.568*10^-3

Find Moles of HC2H302 neutralized by the NaOH?

Answer 1

Because the acid is monoprotic (only 1 acidic hydrogen), the moles of acid are equal to the moles of NaOH.

Answer 2

so how do i figure this out

Answer 3

so answer to find moles of HC2H302 neutralized by the NaOH is 1.568*10^-3

Answer 4

now how do I find the molarity of dill HC2H302

Answer 5

use the molarity equation knowing the moles and the volume you used.

divide the moles by the volume (in liters).

Answer 6

whats the volume of the acid?

Answer 7

hm no thats the volume of base you used

Answer 8

you dont find it, it would have to be measured before doing the titration, or given to you

Answer 9

volume of diluted vingar used in each titration os 20 mL .02 L

Answer 10

I dont know does that help

Answer 11

0.02 L

Answer 12

that is it

Answer 13

is is then 0.001567588/.002

Answer 14

equals 0.783794

Answer 15

you wrote too many zeroes

0.001567588/.02=0.0783794

Answer 16

that is the molarity of dil HC2H3O2

Answer 17

yes

Answer 18

AND THE moles od HC2H302 neutalized by NaOH IS 1.568*10^-3