Question

Where are the asymptotes of f(x) = tan 4x from x = 0 to x = pi over two?
@aum can you check this one please

Answer 1

Try writing tan in terms of sin and cos

Answer 2

That is a first step

Answer 3

once you have it in fractional form
the equation you need to solve is bottom=0 for your asymptotes

Answer 4

No the final answer @freckles

Answer 5

I'm not giving you the answer.
You must get the answer. I'm showing you what to do (or telling you what to do).
Have you wrote it in terms of sin and cos yet?

Answer 6

I know the answer I just want to know what I did was correct

Answer 7

ok then show me

Answer 8

I follow the same steps you given above and got x = pi over 4, x = 3 pi over 4 @freckles

Answer 9

@freckles u coming

Answer 10

you are looking for when cos(u) is 0?
because cos(pi) is -1 not 0

Answer 11

tan 4x = sin 4x / cos 4x
Vertical asymptotes exist when the denominator cos(4x) is zero.

In the interval [0, 2pi], cos(z) = 0 when z = pi/2 or z = 3pi/2
Therefore, cos(4x) = 0 when 4x = pi/2 or 4x = 3pi/2
x = pi/8 or x = 3pi/8. Both these x values are within the specified interval of [0. pi/2]