Question

Please help number nine says the position of an object at time t moving along a line is given by the function s(t)=-16t^2+128t find the average velocity of the object over the following intervals
[1,4]
[1,3]
[1,2]
[1,1+h]

Answer 1

@e.mccormick

Answer 2

If can just help with first one I could use that as sample I am looking at book example but not understanding it

Answer 3

The average velocity over an interval is given by the slope of the secant line over the interval:
\[v_{avg}=\frac{s(b)-s(a)}{b-a}\]
where the interval is \([a,b]\).

Answer 4

With \(s(t)=-16t^2+128t\) and the first interval \([1,4]\), you have
\[v_{avg}=\frac{\left(-16(4)^2+128(4)\right)-\left(-16(1)^2+128(1)\right)}{4-1}\]

Answer 5

Oooo ok

Answer 6

That makes more sense now thanks :) so for this one my answer would be 48 for first one :)

Answer 7

Right. You're welcome!