Question

write .25x^2-.5x-5 in vertex form

Answer 1

do you know what the vertex is?

Answer 2

nope another question is to find vertex

Answer 3

Vertex form: y=a(x-h)2+k (h,k) is the vertex.

Answer 4

so how do i rearrange it? thank you

Answer 5

easiest to find the vertex first
then write in vertex form
do you know how to find the vertex of
\[y=ax^2+bx+c\]?

Answer 6

im not sure no

Answer 7

help please

Answer 8

You already have the equation in that form.
.25x^x - .5x -5

Answer 9

no the vertex form i need to change it from that form to vertex do i have to complete square?

Answer 10

You have to find (h,k) which is the vertex. If you want, you can just use a graphing calculator

Answer 11

So the vertex is about (0, -5)

Answer 12

Plug that into the equation

Answer 13

oh no !!

Answer 14

What?

Answer 15

first coordinate of the vertex is \(-\frac{b}{2a}\) which in your case is \[-\frac{-.5}{2\times .25}=1\]

Answer 16

ohhh

Answer 17

Oh, thanks for correcting me

Answer 18

to find the second coordinate, replace \(x\) by \(1\)

Answer 19

THANK YOU GUYS

Answer 20

you are not done yet though

Answer 21

Okay, after you get the coordinates, you plug them into y=a(x-h)2+k

Answer 22

h is x and k is y
(h, k) = (x, y)

Answer 23

\[y=.25x^2-.5x-5\]
\[y=.25-.5-5=-5.25\] so vertex form is
\[y=.25(x-1)^2-5.25\]

Answer 24

yay great job thank you thank you thank you!!!! also x intercepts are when you set the equation to 0 and solve?

Answer 25

or when you fill in 0 for x?

Answer 26

It's when you make y=0

Answer 27

To find the y intercept, you make x=0

Answer 28

i appreciate you all immensely thank you!!!!

Answer 29

Good job with doing the work! :)