Question

Gauss's law help please!!(drawing included)

Answer 1

an insulating spherical shell has an outer radius b = 2.3a, where a =2.5mm is the radius of the empty cavity as shown. The material of this shell is insulating, with a uniform positive charge density, p=3.22 uC/m^3
use gauss's law to find the magnitude of the electrostatic field E at the following distances r from center

a) r = a/3
b)r=1.75a
c)r=3.5b
now imagine the cavity is instead completely filled with neutral copper. for this case, redo part a.

Answer 2

@Orion1213 this would be the one. I can do all the work if i can just get pointed in the right direction!

Answer 3

I know the answers.
a=0
b=432
c=52.12

Answer 4

as far as I know, there is a formula derived already for a volume charge distribution based on spherical coordinates...

Answer 5

i think it's because the middle is hollow that i have no idea what to do

Answer 6

hmm, when do you need this? just need to review my basics on electromagnetics...

Answer 7

http://www.cabrillo.edu/~cfigueroa/4B/4Bproblem_sets/4B_book_problems/23_problems.pdf

Answer 8

this is on my test tomorrow. it's a 4 question test, and this is the only one I cannot seem to answer correctly

Answer 9

All of the formulas are in a little box. I don't wish to ask you to relearn this though! If a short glance doesn't jog your memory, i will just keep trying!

Answer 10

sorry, don't know where to start... other experts can help you...

Answer 11

Start with

\[\int\limits \int\limits <E,da> = q/\epsilon \]

Answer 12

The first answer is zero. If you make a Gaussian surface with radius 1/3 a there is no enclosed charge thus it is zero.

Answer 13

YES

Answer 14

oops