Question

How many moles of N are in 0.203 g of N2O?

Answer 1

0.203 g N2O x \[\frac{ 1 mol }{ 44.014 g N2O }\] x \[\frac{ 1 mol N2O }{ 2 mol N }\] = .0023 moles of N

Answer 2

Is that right?

Answer 3

oops wait I think the final fraction might need to be flipped

Answer 4

the final amount cant be less..

Answer 5

Okay so multiply \[0.203 g N _{2}O * \frac{ 1 mol N _{2}O }{ 44.014 g N _{2}O } * \frac{ 2 mol N }{ 1 mol N _{2}O } = .0092 mol\]

Answer 6

You just have to do this like the last one i showed you!