Question

Expand. (IMAGE IN COMMENTS)
a. -9c^4/a^3 b^2 + 12c^3 z^2/a b
b. 12b^3 c^3/z^2 - 9a^2 b^2/c^2
c. 12c^3 z^2/b - 9c^4/a^2 b^2
d. undefined
e. none of the above

Answer 1

start by simplifying the denominators in the parentheses
\(\huge \frac{4bc^2}{z^{-2}}=4bc^2z^2\)

Answer 2

alright

Answer 3

and then the next part is 3c^3/a^2 ?

Answer 4

correct.
so now we have \(\huge \frac{3b^{-2}c}{1}(4bc^2z^2-\frac{3c^3}{a^2}) \)

Answer 5

okay so when i went from there the answer i'm getting is B?

Answer 6

\[\huge \frac{3c}{b^2}(\frac{4a^2bc^2z^2}{a^2}-\frac{3c^3}{a^2})\]
\(\huge \frac{3c}{b^2}(\frac{4a^2bc^2z^2-3c^3}{a^2})\)
\(\huge (\frac{3c(4a^2bc^2z^2-3c^3)}{a^2b^2})=\frac{(12a^2bc^3z^2-9c^4)}{a^2b^2})=\)

Answer 7

so the right answer should be C then?

Answer 8

unless I messed up, yeah