Question

sin x cos 2x + cos x sin 2x = 1/2
between 0<= x< 360
I got up to
sinx(2cos^2-1)+cosx(2cosxsinx)=1/2
2cos^2xsinx-sinx+2cos^2xsinx=1/2
4cos^2xsinx-sinx=1/2
sinx(4cos^2x-1)=1/2
2sinx(4cos^2x-1)=1

Answer 1

well I did go more forward by distributing
(8cos^2xsinx-2sinx)=1
sin2x(4cosx)-2sinx=1
(But I dont think this is right though)