Question

http://math.stackexchange.com/questions/930314/find-a-solution-gx-that-satisfies-the-pde-u-x-3u-y-u-1

Answer 1

We just need to find 2 solutions in the form of 1=2e^x @dan815

Answer 2

I meant g(x) = -1+2e^x

Answer 3

5. Write down two different solutions of the PDE in problem 4 when $g(x) = -1+2e^x$\\

does this mean I have to resolve the whole damn problem again?

Answer 4

because we first have u(x,3x) = g(x) . Now we got u(x,3x) = -1+2e^x to deal with

Answer 5

so wait I have to do something like since we have u(x,3x) = -1+ke^x already

Then -1+ke^x = 1+2e^x.

\[2e^x-e^{x}k=-2 \rightarrow -e^{x}k=-2-2e^x \]
\[\rightarrow k =\frac{-2}{-e^{x}} -\frac{-2e^x}{-e^{x}} \rightarrow k = \frac{2}{e^{x}}-2 \rightarrow k =2e^{-x}-2 \]

Answer 6

but now what?

Answer 7

@dan815 hellllooooooooo