Suppose that the x-intercepts of the graph of y=f(x) are 4 and 6. What are the x-intercepts of y=f(x+5)
An x-intercept has the form \((x,0)\). This means when you plug in this value of \(x\) (the intercept), you have \(f(x)=0\). So you know that \(f(4)=f(6)=0\).
If the x-intercepts are 4 and 6, then f(x) = (x-4)(x-6)
f(x+5) shifts f(x) to the LEFT by 5 units. Therefore, the intercepts will shift accordingly (by 5 units to the left).
@Cosmichaotic I don't think we can assume the function is quadratic based solely on two known roots.
Im still very lost. On the back it says the answer is (2,10) and I do not understand how to get that answer.
Have you done translation of function, reflection of function, etc. yet?
We went over it for like 5 minutes.
If f(x) is the parent function, then, for example, f(x+5) moves the function to the LEFT by 5 units. f(x-5) moves the function to the RIGHT by 5 units. f(x) + 5 moves the function UP by 5 units f(x) - 5 moves the function DOWN by 5 units
That makes sense
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