Question

#1
the final burret reading mL is 31.12
initial buret reading mL IS 15.72
volume of titrant mL is 15.49
Moles of NaOH used is 1.568*10^-3 mol
moles of HC2H3O2 neutralized by the NaOH is 1.568*10^-3 mole
molarity of dil HC2H3O2 is .0784 M

#2
final buret reading is 15.53
initial buret reading mL is 0.00
volume of titrant mL is 15.53
Moles of NaOH used is 1.57*10^-3
Moles of HC2H302 neutralized by the NaOH is 1.57*10^-3
molarity of dil HC2H3O2 is .0785 M

Answer 1

how did we find the moles of HC2H302

Answer 2

what exactly is the question?

Answer 3

are you suppose to check which of the 4 choices is true?

Answer 4

I am not sure what you are asking

Answer 5

moles of HC2H3O2= 1.568*10^-3 mole M1
molecular mass of HC2H3O2 = 1 + (1282) +3+(16*2) =
molarity of dil HC2H3O2 is .0784 M = moles/volume
incomplete

Answer 6

incomplete means not finished not complete there should be more

Answer 7

the volume is 15.49 i think this would be V1

Answer 8

m2 = Molarity * molecular mass* volume

Answer 9

what is the molecular mass for
error above molecular mass of HC2H3O2 = 1 + (12*2) +3+(16*2) =
60

Answer 10

let me try and get you some help

Answer 11

well read some of the post above

Answer 12

@cutepochacco can you please help to clarify

Answer 13

@jim_thompson5910, @satellite73 can you or do you know who can help in Chem?

Answer 14

Hero said "Definitely not me. I'm not a fan of chemicals. However, she can try her luck on Slader"
Jim said "sorry I don't know chem or anyone who is good at it maybe the chem section has someone?"

Answer 15

did you find m1 and v1 above?

Answer 16

m1 = 1.568 * 10^-3 * 60.06
v1 = 15.72ml
v2 = 31.12 ?

Answer 17

triciaal is right nd defined whole question clearly so plz read carefully

Answer 18

moles = molarity * volume

Answer 19

ml to liter * 10^-3 yes
and this was already stated

Answer 20

@aaronq will you please review and advise sorry this is so long please help

Answer 21

as stated before what exactly is the question?
what you are calculating is already given

Answer 22

volume used is 20ml = 0.02L
molarity =
moles = volume * molarity

Answer 23

@Phebe can you help please?

Answer 24

I tried earlier to get you help. I don't remember much of this stuff not fresh on my mind. I want you to have the right steps so you can learn what to do. Find someone in Chemistry. you can tag me for Math.

Answer 25

molarity of standardized NaOH solution is 0.1012 M
Volume of diluted vinegar used in each titration 20 mL 0.2 l

Answer 26

ehh, sorry not fresh enough on my mind. would have to do some reading.

Answer 27

M*V=M'*V'

Answer 28

yes ,m1v1=m2v2

Answer 29

so what is
m1
v1
m2
v2
in the problem

Answer 30

that i am confused about

Answer 31

do not get stressed or discouraged.
chemistry is really not hard. lot to understand yes but it's not recent enough for me to help you properly. I would love to help but I would have to review the material and I really don't have time to do that. you also need to read slowly to absorb more.

Answer 32

is v1 = 15.72ml
is v2 = 31.12

Answer 33

Create a table:
x (x-mean) (x-mean)^2
.0784
.0785
.0789
.07895

Add up the last column and plug it into the standard deviation formula

Answer 34

.0784
.0785
.0789
.07895 ADDED TOGETHER is 0786875 M

Answer 35

I need to find the Moles of HC2H302 neutralized by the NaOH?

Answer 36

the final burret reading mL is 31.12
initial buret reading mL IS 15.72
volume of titrant mL is 15.49
Moles of NaOH used is 1.568*10^-3 mol

Answer 37

i FOUND THIS Moles of NaOH used is 1.568*10^-3 mol

Answer 38

Now I need to find what the Moles of HC2H302 neutralized by the NaOH?

Answer 39

Havn't even taken chemistry - so sorry, -wish i could help ,-,

Answer 40

what do you want to calculate?

Answer 41

@kellyconnelly

Answer 42

Hey. You can calculate it by using the formula M1V1 = M2V2

Answer 43

how